EMRFD Message Archive 7233

7233 2012-02-10 08:24:11 Jim Miller Tapping a tank? Message Date From Subject The March issue of QST has an article on vertical matching that had me puzzled for a while but I think I'm finally getting it figured out. The 40m match was a straight forward L-match and I could replicate the values with TLW. I attempted to do the same for the 160 and 80 meter sections before realizing that those configurations were quite different. For those the author chose to resonate the capacitive reactance of the antenna with a suitable inductor which was then tapped near its bottom end, autotransformer-style, to match to 50ohms. My question: is the tap point calculable in general or is it a matter of trial and error with an antenna analyzer? Basically "you know it's down there somewhere, go find it." I read thru EMRFD and the earlier RFD and couldn't find much on this topic. Ditto the ARRL Antenna Book and Handbook. tnx and 73 jim ab3cv [Non-text portions of this message have been removed] IF you knew the resistive part of the antenna impedance, you could find a first approximation of the tap point by pretending the coil is an ideal autotransformer: multiply the total number of turns by the square root of antenna resistance divided by 50 ohms. That is, if the antenna resistance was 5000 ohms, the square root of 5000/50 = 10, s you'd tap up 10% on the coil. If the coil is a toroid with fairly good coupling between turns, this is fairly accurate. I would a coil on a T200-6 core whose reactance would cancel the slight capacitance of my close-to-a-halfwave vertical, then putting the tap at the point indicated by the calculation above. If you don't know the antenna resistance then it becomes a matter of cut and try with whatever instrumentation you have. Toughest would be an SWR bridge, 'cause then you don't know if you're too high or too low and have to diddle around more to figure out where the tap goes. W7AAZ Another way to look at the 160m circuit is as an L-match. From the article, the impedance at 1.9 MHz is 10.688 -j508.59, so picture an L network matching the real part, 10.688 ohms, to 50 ohms. The series arm will be capacitive and the shunt arm inductive. Bear with me now, I know the circuit shows a series inductor but in combination with the antenna's reactance, the net result is still capacitive. First, we need to find the Q needed to match 10.688 to 50 ohms: Q = SQRT( 1 + 50 / 10.688 ) = 2.3829 Now that we know the Q, the reactances are: XLshunt = 50 / Q = j20.983 and XCseries = 10.688 * Q = -j25.468 So, at 1.9 MHz the shunt inductor is 20.983 / ( 2 * pi * 1.9e6 ) = 1.7576 uH. Now we need an inductive reactance to cancel most of the antenna's -j508.59 and leave a result of -j25.468: XLseries = -j25.468 - ( -j508.59 )= j483.12, and at 1.9 MHz the series inductor is 483.12 / ( 2 * pi * 1.9e6 ) = 40.469 uH. Of course, that's just an example and I took the liberty of ignoring the shunt capacitance used in the article to tune the network. Including that makes the calculation more complicated. I would do it by converting the antenna's impedance to admittance, do the same with the tuning capacitance, combine them, then convert back to impedance and calculate the L-network as above. If you'd rather not go through the mental exercise, the calculati john that was very helpful! thanks! jim ab3cv [Non-text portions of this message have been removed] this is precisely the way i feed my 'short' marconi T on 160m. As a crude method to 'gitter done', the easy thing to do is first resonate the antenna, slightly above the desired freq. then, add the shunt inductor, and tweak for best match. and perhaps re-tune the series L to center the frequency in the range of interest. to me, the amount of inductance across the feedpoint seems, intuitively, remarkably  small....like 'wow, this is almost a short, the XL is so small.....' but it works nicely...FWIW....73 w5xz, dan