EMRFD Message Archive 2624
Message Date From Subject 2624 2009-01-23 14:32:50 Ivan Rogers Basic Low Pass Filter Design I am trying to get my head around different methods of Low pass filter
design when using source and load terminations of unequal resistance.
First, I understand the use of Bartlet's Bisection Theorem in EMRFD
Page 3.6 Fig 3.9 when you first work out the filter design using
terminations of equal resistance and then using the theorem to make a
simple tranformation on the left hand side of the filter network. This
makes sense to me.
In other RF design publications another way of calculating LP filters
is to use normalised tables that have normalised values based on a
source/load ratio when the terminations are unequal.
I.E. for 50R terminations at each end Rs/Rl=1
Buterworth values are:
.62 1.62 2.00 1.62 .62
For 15R (Rs) termination and 50R (Rl) termination Rs/Rl=.3
Buterworth values are:
1.09 .29 4.84 .54 5.31 (Ref RF Circuit design, Chris Bowick)
My question is I would expect when using these normalised values with
equations 3.1 and 3.2 (EMRFD page 3.4) is to end up with the same
component values as when I used the Bartlet's theorem method above but
Is it because say Bartlet's theorem just transforms the Left hand side
of the filter network for impedance trasnformation and that the
normalised value ratios use the whole of the circuit for impedence
transformation. If so, is there any advantage for one over the other?
Just trying to get to grip with the basics first on the 2 approaches
above before I start experimenting on the bench.
2633 2009-01-24 10:30:30 Wes Hayward Re: Basic Low Pass Filter Design Hi Ivan and gang,
Very good question. Almost all of the filter work that I've done
has been with doubly terminated ladders, although I've done some work
with singly terminated ones, which is just the most extreme member of
the tables that you mention. I've used Bartlet where modest
asymmetry was needed.
I elected to look at this situation through study of some design
examples. I started with the Bartlet case. I designed a filter
with N=5 for a 1 dB Chebyshev shape with 3 dB cutoff of 10 MHz. I
used a lot of ripple, for that yields a design with "warts" that are
easy to see in graphs. I then duplicated the filter in software, but
moved one termination from 50 to 100 Ohms. I did plots in SPICE to
get the multicolor display of several waveforms. The Bartlet low
pass looked exactly like the original one so far as the output
response except that it was displaced in amplitude from the equally
But the input reflection coefficient was a different story. The
equally terminated case was just what we normally see with a Chebyshev
a very good match at those frequencies where the amplitude peaks
occur. But the match had degraded severely for the asymmetric
termination case. When you think about it though, this makes perfect
sense. Consider the behavior at 0 frequency. The reactive
components effectively disappear, leaving just the source and load.
These resistors are now different, so the match must be poor.
Next I went to Zverev and found some low pass tables. The most
extreme ripple he had was 0.5 dB, so I selected those. I first did
a filter design like the other case, a 10 MHz 3 dB cutoff with equal
terminations. The results were as expected. I then shifted to an
example with a source resistance that was half the load. This data
was used to design a filter with 50 Ohm source and 100 Ohm load.
The results for both filters were plotted on the same graph, along
with curves showing the magnitude of the reflection coefficient at the
50 Ohm end. Again, the transfer curves were identical with each
other except for a displacement in amplitude. But the input impedance
match was now severely degraded.
The two filters were very different from each other so far as
component values go.
Now what I need to do is to blend the curves together and come up with
one plot that has everything on it. But alas, today I have some
painting chores to chase.
Incidentally, while chasing these demons, I noticed that my software
for the design of the low pass filters generates component values that
are identical with those of Zverev with a design based upon the 3 dB
cutoff frequencies. However, I noted that the normalized component